25^cos(3п/2+x)=5^1-cos2x Корни на отрезке: [-5п; -3п/2]

5^2cos(3π/2+x)=5^1-cos2x 2cos(3π/2+x)=1-cos2x 2sinx=2sin²x 2sin²x-2sinx=0 2sinx(sinx-1)=0 sinx=0⇒x=πn,n∈z -5π≤πn≤-3π/2 -5≤n≤-3/2 n=-5⇒x=-5π n=-4⇒x=-4π n=-3⇒x=-3π n=-2⇒x=-2π sinx=1⇒x=π/2+2πk,k∈z -5π≤π/2+2πk≤-3π/2 -10≤1+4k≤-2 -11≤4k≤-3 -11/4≤k≤-3/4 k=-2⇒x=π/2-4π=--7π/2 n=-1⇒x=π/2-2π=-3π/2