2logx(27)-3log27(x)=1

2 / log27(x) - 3log 27 (x) = 1 Домножим на log 27 (x): 2 - 3log² 27 (x) = log 27 (x) log 27 (x) = t 3t² + t - 2 = 0 D = 1 + 24 = 25 t = (-1-5)/6 = - 1                 t = (-1 + 5)/6 = 2/3 log 27 (x) = - 1                   log 27 (x) = 2/3 x = 1/27                             x = 27^ (2/3) = ∛27² = 3² = 9