2(sin^3x+cos^3x)=sin2x(sinx+cos x)

2sin^3x-2sinx+1-sin^2x=02sinx(sin^2x-1)-(sin^2x-1)=0(2sinx-1)(sin^2x-1)=0sin^2x=1 sinx=1  x1=-3,5П              sinx=-1  x2=-2,5П sinx=1/2           x3=-19П/6