3 sin (2 [latex] \alpha [/latex] - [latex] \frac{ \pi }{4} [/latex]) + 2 cos (3 [latex] \alpha [/latex] - [latex] \pi [/latex]) если [latex] \alpha [/latex] = [latex] \frac{ \pi }{4} [/latex]

Question

3 sin (2 [latex] \alpha [/latex] - [latex] \frac{ \pi }{4} [/latex]) + 2 cos (3 [latex] \alpha [/latex] - [latex] \pi [/latex]) если [latex] \alpha [/latex] = [latex] \frac{ \pi }{4} [/latex]

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Ответ(ы) на вопрос:

Accepted Answer

... = 3*sin((2*π/4) - (π/4)) + 2*cos((3*π/4) - π) = = 3*sin(π/4) + 2*cos(-π/4) = 3*√2 / 2 + 2*√2 / 2 = 5√2 / 2 косинус --- функция четная, т.е. cos(-x) = cos(x)