{3(2a-5)+4(7-3b)=7 2(4+b)-7(1+8a)=-53 Решите систему уравнений

[latex] \left \{ {{3(2a-5)+4(7-3b)=7} \atop {2(4+b)-7(1+8a)=-53}} \right. \left \{ {{6a-15+28-12b=7} \atop {8+2b-7-56a=-53}} \right. \left \{ {{6a-12b=-6}|:6 \atop {2b-56a=-54}|:2} \right. \left \{ {{a-2b=-1} \atop {b-28a=-27}} \right. \left \{ {{a=2b-1} \atop {b-28a=-27}} \right. b-28(2b-1)=-27 b-56b+28=-27 -55b=-27-28 -55b=-55 b=1 a=2*1-1 a=1 [/latex] Ответ:(1;1)