3n^2-3m^2/6m^3+6n^3Сократите дроби

[latex]{3n^2-3m^2\over6m^3+6n^3}={1\over2}{(n-m)(n+m)\over(n+m)(n^2-nm+m^2)}={n-m\over2n^2-2nm+2m^2}[/latex]