√3tgx-3/(-sinx+√3)=0 [0;2π]

[latex] \frac{\sqrt3tgx-3}{-sinx+\sqrt3} =0\; ,\; \; \; ODZ:\; \left \{ {{x\ne \frac{\pi}{2}+\pi n,\; n\in Z} \atop {sinx\ne \sqrt3\approx 1,7\; (verno\; dlya\; x\in R)}} \right. \; ,x\ne \frac{\pi}{2}+\pi n\\\\\sqrt3tgx-3=0\\\\tgx=\frac{3}{\sqrt3}=\sqrt3\\\\x=\frac{\pi}{3}+\pi k,\; k\in Z\\[/latex] xЄ[0,2π]  ,  x= π/3 ; (4π)/3.