3x^2 ≥ | x^2+2x | + 12

[latex]3x^2\geq |x^2+2x|+12[/latex] [latex]\left \{ {{x^2+2x\geq0} \atop {3x^2\geq x^2+2x+12}} \right.[/latex]  [latex]\left \{ {{x(x+2)\geq0} \atop {x^2-x-6\geq 0}} \right.[/latex] [latex]\left \{ {{x(-\infty;-2]\cup[0;+\infty)} \atop {x^2-x-6\geq 0}} \right.[/latex] D = 25 x = 3 x = -2    [latex]\left \{ {{x^2+2x<0} \atop {3x^2\geq -x^2-2x+12}} \right.[/latex]  [latex]\left \{ {{x(x+2)<0} \atop {2x^2+x-6\geq 0}} \right.[/latex] [latex]\left \{ {{x(-2;0)} \atop {2x^2-x-6\geq 0}} \right.[/latex] D = 49 x = 3/2 - не принадлежит области определения x = -2   Ответ: x = -2; x = 3