3x(во второй степени)-2х=4

Решение во вложении))

[latex]3x^{2}-2x=4 [/latex] [latex]3x^{2}-2x-4=0 [/latex] [latex]D=b^{2}-4ac=4+48=52[/latex] [latex] \left \{ {{x=\frac{2+\sqrt{52} }{6} } \atop {x=\frac{2-\sqrt{52} }{6} }} \right. [/latex] [latex] \left \{ {{x=\frac{2+2\sqrt{13} }{6} } \atop {x=\frac{2-2\sqrt{13} }{6} }} \right. [/latex] [latex] \left \{ {{x=\frac{1+\sqrt{13} }{3} } \atop {x=\frac{1-\sqrt{13} }{3} }} \right. [/latex]