4cos(x/2+p/6)+√12=0 помогите, плиииз

[latex]4cos( \frac{x}{2}+ \frac{ \pi }{6})+ \sqrt{12}=0 [/latex] [latex]4cos( \frac{x}{2}+ \frac{ \pi }{6})=- \sqrt{12} [/latex] [latex]cos( \frac{x}{2}+ \frac{ \pi }{6})=- \frac{ \sqrt{12} }{4} [/latex] [latex]cos( \frac{x}{2} + \frac{ \pi }{6})=- \frac{ \sqrt{3} }{2} [/latex]  [latex] \frac{x}{2} + \frac{ \pi }{6} =+- \frac{5 \pi }{6}+2 \pi n,n[/latex] [latex]\frac{x}{2} =+- \frac{5 \pi }{6}- \frac{ \pi }{6} +2 \pi n,n [/latex] [latex]x=+- \frac{10 \pi }{6}- \frac{ 2\pi }{6} +4 \pi n,n[/latex] [latex]x =+- \frac{5 \pi }{3}- \frac{ \pi }{3} +4 \pi n,n[/latex]