(4х+1)(х+5)=(4х+1)(3х+2)

[latex](4x+1)(x+5)=(4x+1)(3x+2) |:(4x+1) \\ x+5=3x+2 \\ x-3x=2-5 \\ -2x=-3 \\ x=1.5[/latex]

4x²+20x+x+5=12x²+8x+3x+2 4x²-12x²+20x+x-8x-3x=2-5 -8x²+10x=-3 -8x²+10x+3=0 D=b²-4ac=100-4*(-8)*3=100+96=4>0, 2 корня x₁=[latex] \frac{-b+ \sqrt{D} }{2a} = \frac{-10+2}{-16}= \frac{-8}{-16}= \frac{1}{2}=0,5 [/latex] x₂=[latex] \frac{-b- \sqrt{D} }{2a}= \frac{-10-2}{-16}= \frac{-12}{-16}= \frac{3}{4} = 0,75[/latex] Ответ: x₁=0,5, x₂=0,75