4sin^3x=sinx-cosx помогите плиииз

4sin^3 x - (sinx + cosx) = 0 4sin^3 x - sinx - cosx = 0 (4sin^3 x - sinx) - cosx = 0 4sin x * (sin^2 x - 1) - cosx = 0 - 4sin x * (1- sin^2 x) + cosx = 0 -4sin x * cos^2 x + cosx = 0 cos x * (1 - 4sin x*cos x) = 0 Или cos x = 0 => x= п/2+2пn Или 1 - 4sin x*cos x = 0 => 1 - 4*1/2*(sin 0 + sin 2x) = 0 1 - 2sin 2x = 0 sin 2x = 1/2 2x = п/6 => x = п/12+ 2пn