5^(2x-y)=1/5, 5^2x +5^y=6sqrt(5) cистема найти х1 и х2

[latex] 5x^{2x-y} = 5^{-1} [/latex] [latex]5^{2x} + 5^{y} =6 \sqrt{5} [/latex] [latex]2x-y=-1[/latex] [latex]y=2x+1[/latex] [latex]5^{2x} + 5^{2x+1} =6 \sqrt{5} [/latex] [latex]y=2x+1[/latex] [latex]5^{2x}(1+ 5) =6 \sqrt{5} [/latex] [latex]y=2x+1[/latex] [latex]5^{2x}*6 =6 \sqrt{5} [/latex] [latex]y=2x+1[/latex] [latex]5^{2x} = 5^{ \frac{1}{2} } [/latex] [latex]2x= \frac{1}{2} [/latex] [latex]x= \frac{1}{4} [/latex] [latex]y=1.5[/latex] Ответ:(0,25;1,5)