5Х²+20x=0 5Х²-8x+3=0 x(x-1) -------------=0 (x-1)(x-2)

[latex]x(5x-20)=0 \\ x=0; 5x-20=0 \\ 5x=20 \\ x=4 \\ 5x^2-8x+3=0 \\ D= 64-60 \\ \sqrt{D}=\sqrt{4}=2 \\ x_1= \frac{8+2}{10}=1 \\ x_2= \frac{8-2}{10}= \frac{3}{5} \\ \frac{x-(x-1)}{(x-1)(x-2)}=0 \\ \frac{x}{x-2}=0 \\ \left \{ {{x=0} \atop {x-2\neq0}} \right \\ \left \{ {{x=0} \atop {x\neq2}} \right[/latex]