6x2+7x-3=0 Пожалуйстааа :'(

d=49-4*6*(-3)=49+72=121 x1=(-7-11)/12=3/2=1,5 x2= (-7+11)/12=1/3

[latex]6 x^{2} + 7 x - 3 = 0[/latex] [latex]a=6 ; b=7; c= -3[/latex] [latex]D= b^{2} - 4ac[/latex] [latex]D= 7^{2} - 4*6*(-3) = 49+72=121[/latex] [latex] x_{1} = \frac{-b+ \sqrt{D} }{2a} [/latex] [latex] x_{2} = \frac{-b- \sqrt{D} }{2a} [/latex] [latex] x_{1} = \frac{-7+11}{12} = \frac{4}{12} = \frac{1}{3} [/latex] [latex] x_{2} = \frac{-7-11}{12} = \frac{-18}{12} = -\frac{3}{2} = -1 \frac{1}{2} [/latex]