A:b=3 (2a+3b):(3a+2b) Срочно!

[latex](2a+3b):(3a+2b)=\frac{2a}{3a}+\frac{2a}{2b}+\frac{3b}{3a}+\frac{3b}{2b}=\frac{2}{3}+\frac{a}{b}+\frac{b}{a}+\frac{3}{2}=2\frac{1}{6}+\frac{a}{b}+\frac{b}{a}[/latex] [latex]\frac{a}{b}=3 \\ \frac{ab}{b}=3b \\ a=3b[/latex] при [latex]a=3b[/latex] имеем: [latex]2\frac{1}{6}+\frac{3b}{b}+\frac{b}{3b}=2\frac{1}{6}+3\frac{1}{3}=2\frac{1}{6}+3\frac{2}{6}=5\frac{3}{6}=5.5[/latex]