А)lim x→3 x^2-x-6/x-3 б)lim→∞ x^3-x^2/x^4-x

[latex]1) \lim_{x \to 3} \frac{(x-3)(x+2)}{x-3}=\lim_{x \to 3}x+2=5[/latex] [latex]2)\lim_{x \to \infty} \frac{x^3-x^2}{x^4-x}=\lim_{x \to \infty} \frac{x(x-1)}{(x-1)(x^2+x+1)}=\lim_{x \to \infty} \frac{x}{x^2+x+1}= \\ =\lim_{x \to \infty} \frac{ \frac{1}{x}}{1+ \frac{1}{x}+ \frac{1}{x^2} }= 0[/latex]