C1 решите пожалуууйста

ОДЗ: x ≠ ±2 [latex] \frac{36}{4 - x^2} + 2 = \frac{1-x}{x+2} - \frac{9}{x-2} [/latex] [latex] \frac{36}{(2 - x)(2 + x)} + 2 = \frac{(1-x)(2 - x)}{(x+2)(2 - x)} + \frac{9(x+2)}{(x + 2)(x - 2)} [/latex] [latex] \frac{36 - (1-x)(2-x) - 9(x+2)}{(2 - x)(2 + x)} = -2[/latex] [latex]\frac{36 - 2 + x + 2x - x^2 - 9x - 18}{(2 - x)(2 + x)} = -2 [/latex] [latex]\frac{16 - 6x - x^2 }{4 - x^2} = -2[/latex] [latex]16 - 6x - x^2 = -2(4 - x^2)[/latex] [latex]16 - 6x - x^2 = -8 + 2x^2[/latex] [latex]3x^2 + 6x - 24 = 0[/latex] [latex]x^2 + 2x - 8 = 0[/latex] x₁ + x₂ = -2 x₁*x₂ = -8 x₁ = 2 - не уд. ОДЗ x₂ = -4 Ответ: x = -4.