Cos2x×cos x=sin2x×sin x

Решение co2x*c0sx = si2x*sinx (2cos∧2x - 1)*cosx = 2* sinx*cosx*sonx (2cos∧2x - 1)*cosx = 2 sin∧2x*cosx делим на cosx ≠ 0 2*(cos∧2x - sin∧2x) - 1 = 0 2*(1 - 2 sin∧2x) - 1 = 0 2 - 4*sin∧2 - 1 = 0 4*sin∧2x = 1 sin∧2x = 1/4 1) sinx = - 1/2 x = (-1)∧(n+1) *arcsin(1/2) +  πn, n∈Z x = (-1)∧(n+1) *π/6 + πn, n∈Z 2)  sinx =  1/2 x = (-1)∧(n) *arcsin(1/2) +  πk, k∈Z x = (-1)∧(n) *π/6 + πk, k∈Z