(cos75*cos15-cos15*cos105)/(sin18*sin63+sin108*sin27)
(cos75*cos15-cos15*cos105)/(sin18*sin63+sin108*sin27)
Ответ(ы) на вопрос:
(cos75*cos15-cos15*cos105)/(sin18*sin63+sin108*sin27)= =(сos(90-15)cos15-cos15cos(90-15))/(sin(90+18)sin27+sin18sin(90-27))= =(sin15cos15+cos15sin15)/(cos18sin27+sin18cos27)=sin30/sin(45)=(1/2)/(sqrt(2)/2)= =sqrt(2)/2
Не нашли ответ?
Похожие вопросы