Егэ по математике №15

[latex]log_3^2x +2 \ \textgreater \ 3log_3x \\ x\ \textgreater \ 0 \\ log_3^2x -3log_3x + 2\ \textgreater \ 0 \\ log_3x = t \\ t^2 - 3t + 2 \ \textgreater \ 0 \\ D = 9 -8 =1 \\ t_1 = \frac{3+1}{2} = 2 \\ t_2 = \frac{3-1}{2} = 1 \\ log_3x = 1 \\ x=3 \\ log_3x = 2 \\ x=9 [/latex]