Формула куба помогите решить-------1-(4a+1/3b)^3 2-(2x-1/2y)^3 3-(2/3x-3y)^3 4-(1/3m+1/2n)^3 5-(1/5a+5b)^3

(a+b)²=a³+3a²b+3ab²+b³ (a-b)³=a³-3a²b+3ab²-b³  (4а+1/3 b)³=64a³ + 3*16a² *1/3 b + 3*4a * 1/9b² + 1/27b³=64a³ + 16a²b + 4/3 ab² + 1/27 b³     (2x-1/2y)³=8x³ - 2x²y +1/2 ay² - 1/8 y³ (2/3 x - 3y)³=8/27 x³ - 4/3 x²y+6xy² - 27y³ (1/3 m+1/2 n)³=1/27 m³+1/18 m²n+1/12 mn²+1/8 n³ (1/5 a+5b)³=1/125 a³ +1/5 a²b+5ab²+125b³