Htibnt ehfdytybtlog0.2(x^2+4x)= -1

ОДЗ х²+4х>0 x(x+4)>0 x∈(-∞; -4)∨(0; +∞) [latex]log_{0.2}( x^{2}+4x)=-1 \\ log_{ \frac{1}{5} }( x^{2}+4x)=-1 \\ x^{2} +4x=( \frac{1}{5})^{-1} \\ x^{2} +4x =5 \\ x^{2} +4x-5=0 \\ D=4^2+4*5=36 \\ \\ x_1= \frac{-4+6}{2}=1 \\ x_2= \frac{-4-6}{2}=-5 [/latex]