Как решить : (2x+4)log3(x-4) меньше =0

[latex](2x+4) log_{3} (x-4) \leq 0[/latex] ОДЗ: [latex]x-4\ \textgreater \ 0[/latex] [latex]x\ \textgreater \ 4[/latex] 1 случай: [latex] \left \{ {2x+4 \leq 0} \atop { log_{3}(x-4) \geq 0 }} \right. [/latex] [latex] \left \{ {{2x \leq -4} \atop { log_{3}(x-4) \geq log_{3} 1}} \right. [/latex] [latex] \left \{ {{x \leq -2} \atop {x-4 \geq 1}} \right. [/latex] [latex] \left \{ {{x \leq -2} \atop {x \geq 5}} \right. [/latex]   система неравенств не имеет решений 2 случай: [latex]\left \{ {2x+4 \geq 0} \atop { log_{3}(x-4) \leq 0 }} \right. [/latex] [latex]\left \{ {2x \geq -4} \atop { log_{3}(x-4) \leq log_{3}1 }} \right. [/latex] [latex]\left \{ {x \geq -2} \atop { x-4 \leq 1 }} \right. [/latex] [latex]\left \{ {x \geq -2} \atop { x \leq 5 }} \right. [/latex] x ∈ [latex][-2;5][/latex]  с учетом ОДЗ Ответ: [latex](4;5][/latex]