Как решить уравнение 5х в квадрате+25х-111=-х в квадрате-8х+9

Через дискриминант. [latex] \\ [/latex] [latex] 5x^{2} + x^{2} +25x-111+8x-9=0[/latex] [latex] \\ [/latex] [latex] 6x^{2} +33-120=0[/latex] [latex] \\ [/latex] [latex]D=1089-4*6*(-120)=1089+2880=3969[/latex] [latex] \\ [/latex] [latex] \sqrt{D} = \sqrt{3969} =63[/latex] [latex] \\ [/latex] [latex] x_{1} = \frac{-33+63}{12} = \frac{30}{12} =2,5[/latex] [latex] \\ [/latex] [latex] x_{2} = \frac{-33-63}{12} = \frac{-96}{12} =-8[/latex]

5х²+25х-111=-х²-8х+9 6х²+33х-120=0 Д=33²-4×6×(-120)=1089+2880=3969=63² х1=-33-63/6×2=-96/12=-8 х2=-33+63/6×2=30/12=2,5