ХЕЛП ! ! ! [latex] \frac{5 x^{2} +12x-9}{20} [/latex] = 0

[latex] \frac{5x^2+12x-9}{20}=0 \\ \\ 5x^2+12x-9=0 \\ x_1=-3 \\ x_2= \frac{3}{5} [/latex] Ответ: [latex]-3; \frac{3}{5} [/latex]

[latex] \frac{5 x^{2} +12x-9}{20} =0[/latex] [latex] \left \{ {5 x^{2} +12x-9=0} \atop {20 \neq 0}} \right. [/latex] [latex]5 x^{2} +12x-9=0[/latex] [latex]D=12^{2} -4*5*(-9)=144+180=324[/latex] [latex]x1= \frac{-12- \sqrt{324} }{5*2}= \frac{-12-18}{10}= \frac{-30}{10}=-3[/latex] [latex]x2= \frac{-12+ \sqrt{324} }{5*2}= \frac{-12+18}{10}= \frac{6}{10}=0,6[/latex] Ответ:-3;0,6