Корень из (1/6 - 5x) = 1/6

[latex] \sqrt{ \frac{1}{6}-5x } = \frac{1}{6} ;\frac{1}{6}-5x \geq 0 \\ (\sqrt{ \frac{1}{6}-5x })^{2} = (\frac{1}{6})^{2} \\ \frac{1}{6}-5x = \frac{1}{36} \\ -5x=\frac{1}{36} -\frac{1}{6} \\ -5x=-\frac{5}{36} \\ x=-\frac{5}{36}:(-5) \\ x=\frac{1}{36} \\ [/latex] 1/36 удовлетворяет условию 1/6-5х≥0 Ответ: 1/36