Косинус(х+пи/6)=корень из2/2

[latex]cos(x+ \frac{\pi}{6})= \frac{ \sqrt{2} }{2} \\ x+\frac{\pi}{6}=-\frac{\pi}{4}+2\pi k =\ \textgreater \ x=- \frac{5\pi}{12}+2\pi k \\ x+\frac{\pi}{6}=\frac{\pi}{4}+2\pi n=\ \textgreater \ x= \frac{\pi}{12}+2\pi n[/latex] Ответ: [latex]- \frac{5\pi}{12}+2\pi k; \frac{\pi}{12}+2\pi n, ~~k, n\in \mathbb{Z}[/latex]