[latex]( \frac{1}{2} - \frac{2}{3} ) в [/latex]

[latex] (\frac{1}{2}- \frac{2}{3})^2=( \frac{3-4}{6})^2= (-\frac{1}{6})^2= \frac{1}{36} [/latex] или так [latex]( \frac{1}{2}- \frac{2}{3})^2=( \frac{1}{2})^2-2* \frac{1}{2}* \frac{2}{3}+( \frac{2}{3})^2= \\ \\ = \frac{1}{4}- \frac{4}{6}+ \frac{4}{9}= \frac{9-24+16}{36}= \frac{1}{36} [/latex]