[latex] \frac{2x+1}{2x-1} + \frac{8}{1-4 x^{2} }= \frac{3(2x-1)}{7(2x+1)} [/latex] ПОМОГИИТЕ

[latex] \frac{2x+1}{2x-1}- \frac{8}{(2x-1)(2x+1)}- \frac{3(2x-1)}{7(2x+1)}=0 \\ \\ x \neq 0.5 \\ x \neq -0.5 [/latex] Общий знаменатель: 7(2х-1)(2х+1) [latex]7(2x+1)^2-8*7-3(2x-1)^2=0 \\ 7(4x^2+4x+1)-56-3(4x^2-4x+1)=0 \\ 28x^2+28x+7-56-12x^2+12x-3=0 \\ 16x^2+40x-52=0 \\ 4x^2+10x-13=0[/latex] [latex]D=100+208=308 \\ x_{1}= \frac{-10- \sqrt{308} }{8}= \frac{-10-2 \sqrt{77} }{8}= \frac{-5- \sqrt{77} }{4} \\ x_{2}= \frac{-5+ \sqrt{77} }{4} [/latex]