[latex] \frac{3x^2+x}{4} - \frac{2-7x}{5} = \frac{3x^2+17}{10} [/latex]

[latex]\frac{3x^2+x}{4}-\frac{2-7x}{5}=\frac{3x^2+17}{10}\ \ \ \ \ \ |*20\\5(3x^2+x)-4(2-7x)=2(3x^2+17)\\15x^2+5x-8+28x=6x^2+34\\9x^2+33x-42=0\ \ \ \ \ \ |:3\\3x^2+11x-14=0\\D=121+168=289=17^2\\\boxed{x_1=\frac{-11+17}{3*2}=-1}\\\boxed{x_2=\frac{-11-17}{3*2}=-\frac{28}{6}=-\frac{14}{3}}[/latex]