[latex] \frac{m-2}{6-m} - \frac{m-3}{m+6} + \frac{2m(m-2)}{(m+6)(m-6)} [/latex] Решите пож)

[latex]\frac{m-2}{6-m}-\frac{m-3}{m+6}+\frac{2m(m-2)}{(m+6)(m-6)}=\frac{2-m}{m-6}-\frac{m-3}{m+6}+\frac{2m(m-2)}{(m+6)(m-6)}=\\\ =\frac{(2-m)(m+6)-(m-3)(m-6)+2m(m-2)}{(m+6)(m-6)}=\\\ =\frac{2m+12-m^2-6m-(m^2-6m-3m+18)+2m^2-4m}{(m+6)(m-6)}=\\\ =\frac{-m^2-4m+12-m^2+9m-18+2m^2-4m}{(m+6)(m-6)}=\\\ = \frac{m-6}{(m+6)(m-6)}=\frac{1}{m+6}[/latex]