[latex] \sqrt{2x^{2}+3x+4 }=2x+1 [/latex]

[latex] \sqrt{2x^2+3x+4} = 2x+1[/latex] [latex]2x^2+3x+4 = 4x^2+4x+1[/latex] [latex]2x^2+x-3=0[/latex] D=b²-4ac=1-4*2*(-3)=1+24=[latex] \sqrt{25} [/latex]=5 x₁=[latex] \frac{-1+5}{4} = \frac{4}{4} =1[/latex] x₂=[latex] \frac{-1-5}{4} = - \frac{6}{4} =-1,5[/latex] - пост. корень