[latex] x^{2} -x+9=(x+2) x^2[/latex]

[latex]x^2 - x + 9= (x+2)x^2 \\ x^2 - x + 9 = x^3 + 2x^2 \\ x^2 - x + 9 - x^3 - 2x^2 = 0 \\ -x^3 -x^2 - x + 9 = 0 \\ x^3 +x^2 + x - 9 = 0 \\ x(x^2 +x + 1 - 9) = 0 \\ x_1 = 0 \\ x^2 + x - 8 = 0 \\ D = 1^2 - 4 * (-8) = 1 + 24 = 25 \\ x_2_,_3 = \frac{-1б \sqrt{D} }{2} = \frac{-1б \sqrt{25} }{2}=\frac{-1б 5 }{2} \\ x_2 = 2 \\ x_3 = -3[/latex] Ответ: [latex]-3; 0;2[/latex]