[latex] x^{3} -8[/latex]c[latex]c ^{3} +27 [/latex][latex] x^{3} + 27y ^{3} [/latex][latex]-27 x^{3} -8 y^{3} [/latex][latex]64 x^{6} +27 y^{3} [/latex][latex](a-3) ^{3} +64[/latex]

Question

[latex] x^{3} -8[/latex]c[latex]c ^{3} +27 [/latex][latex] x^{3} + 27y ^{3} [/latex][latex]-27 x^{3} -8 y^{3} [/latex][latex]64 x^{6} +27 y^{3} [/latex][latex](a-3) ^{3} +64[/latex]

[latex] x^{3} -8[/latex] c[latex]c ^{3} +27 [/latex] [latex] x^{3} + 27y ^{3} [/latex] [latex]-27 x^{3} -8 y^{3} [/latex] [latex]64 x^{6} +27 y^{3} [/latex] [latex](a-3) ^{3} +64[/latex]

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Ответ(ы) на вопрос:

Accepted Answer

[latex] x^{3} -8=(x-2)(x^2+2x+4) \\ c ^{3} +27=(c+3)(c^2-3c+9) \\\ x^{3} + 27y ^{3}=(x+3y)(x^2-3xy+9y^2)[/latex] [latex]-27 x^{3} -8 y^{3}=-(3x+2y)(9x^2-6xy+4y^2) \\\ 64 x^{6} +27 y^{3}=(4x^2+3y)(16x^4-12x^2y+9y^2) \\\ (a-3) ^{3} +64=(a-3+4)((a-3)^2-4(a-3)+16)= \\\ =(a+1)(a^2-6a+9-4a+12+16)=(a+1)(a^2-10a+37)[/latex]