[latex](\sqrt(10)-3)^2^x=(\sqrt(10)+3)[/latex]

[latex]\sqrt{10}+3=\dfrac{(\sqrt{10}+3)(\sqrt{10}-3)}{\sqrt{10}-3}=\dfrac{10-9}{\sqrt{10}-3}=(\sqrt{10}-3)^{-1}[/latex]   [latex](\sqrt{10}-3)^{2x}=(\sqrt{10}-3)^{-1}[/latex] [latex]2x=-1[/latex] [latex]x=-\dfrac12[/latex]