Ответ(ы) на вопрос:
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[latex]x+ \sqrt{x+18} \leq 2[/latex]
[latex] \sqrt{x+18} \leq 2-x[/latex]
[latex] \left \{ {{x+18 \geq 0} \atop {2-x \geq 0}} \atop {( \sqrt{x+18})^2 \leq (2-x)^2}} \right. [/latex]
[latex] \left \{ {{x \geq -18} \atop {x \leq 2}} \atop {x+18 \leq4+x^2-4x}} \right. [/latex]
[latex] \left \{ {{x \geq -18} \atop {x \leq 2}} \atop {-x^2+5x+14 \leq0}} \right. [/latex]
[latex]\left \{ {{x \geq -18} \atop {x \leq 2}} \atop {x^2-5x-14 \geq 0}} \right. [/latex]
[latex]x^2-5x-14=0[/latex]
[latex]D=(-5)^2-4*1*(-14)=25+56=81[/latex]
[latex]x_1= \frac{5+9}{2}=7 [/latex]
[latex]x_1= \frac{5-9}{2}=-2 [/latex]
-----------[-18]------------------------[2]------------------------------
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---------+-----------[-2]----------------------[7]-------------+----------
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Ответ: [ -18; -2]
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