Log1/2(x+7) больше -3 помогите пжлст

[latex]log_{ \frac{1}{3}}(x+7)>-3\cdot 1 [/latex] [latex]1=log_{ \frac{1}{3}} \frac{1}{3} [/latex] [latex]log_{ \frac{1}{3}}(x+7)>-3\cdot log_{ \frac{1}{3}} \frac{1}{3} \\ log_{ \frac{1}{3}}(x+7)> log_{ \frac{1}{3}} (\frac{1}{3}) ^{-3} \\ log_{ \frac{1}{3}}(x+7)> log_{ \frac{1}{3}}27\Rightarrow \left \{ {{x+7>0} \atop {x+7<27}} \right. [/latex] [latex] \left \{ {{x>-7} \atop {x<20}} \right. [/latex] Ответ. (-7; 20)