Log₃ ( x² - x - 2 ) ≤ 1 + log₃ [latex]\frac{x+1}{x+2}[/latex] прошу, решите подробно! :)

log₃ ( x² - x - 2 ) ≤ 1 + log₃  x² - x - 2=(x-2)(x+1) log₃ ( x² - x - 2 )=log₃(x+1)+log₃(x-2) log₃ =log₃(x+1)-log₃(x+2) log₃(x+1)+log₃(x-2)<=log₃(x+1)-log₃(x+2)+1 log₃(x-2)+log₃(x+2)<= log₃3 x^2-4<=3 x^2<=7   -sqrt(7)<=x<=sqrt(7) x² - x - 2>0  x<-1 U x>2   -sqrt(7)<=x<-1 U (2;sqrt7]   (x+1)/(x+2)>0 x<-2 U x>-1   [-sqrt(7);-2) U (2;sqrt(7)]