Log3 (x^2+3x) = log 3 (5x+8)

[latex]log_3 (x^2+3x) = log_3 (5x+8)[/latex] ОДЗ: [latex]x(x+3)\ \textgreater \ 0; \left \{ {{x\ \textgreater \ 0} \atop {x\ \textless \ -3}} \right. [/latex] [latex]5x+8\ \textgreater \ 0;x\ \textgreater \ -1.6[/latex] [latex]x\ \textgreater \ 0[/latex] [latex]x^2+3x=5x+8[/latex] [latex]x^2-2x-8=0[/latex] [latex](x-4)(x+2)=9[/latex] [latex]x_1=4;x_2=-2[/latex] С учетом ОДЗ: [latex]x=4[/latex]