Log3(x^2-x-3)+log3(2x^2+x-3) больше =log3(x^2-2)^2+2+log1/3 4

ОДЗ x²-x-3>0 D=1+12=13 x1=(1-√13)/2 U x2=(1+√13)/2 x<(1-√13)/2 U x>(1+√13)/2 2x²+x-3>0 D=1+24=25 x1=(-1-5)/4=-1,5 U x2=(-1+5)/4=1 x<-1,5 U x>1 x²-2≠0⇒x≠-√2 U x≠√2 x∈(-∞;-1,5) U ((1+√13)/2;∞) log(3)[(x²-x-3)(2x²+x-3)]≥log(3)[9(x²-2)²/4]      2=log(3)9 U log(1/3)4=-log(3)4 (x²-x-3)(2x²+x-3)≥9(x²-2)²/4 4(x²-x-3)(2x²+x-3)≥9(x²-2)² 8x^4+4x³-12x²-8x³-4x²+12x-24x²-12x+36-9x^4+36x²-36≥0 -x^4-4x³-4x²≥0 x^4+4x³+4x²≤0 x²(x²+4x+4)²≤0 x²(x+2)²≤0 x=0 ∉ ОДЗ  x=-2 Ответ х=-2 Проверка log(3)(4+2-3)+log(3)(8-2-3)=log(3)3+log(3)3=1+1=2 log(3)(4-2)²+2-log(3)4=log(3)4+2-log(3)4=2 2≥2