Logx (x-2) * logx (x+2) =0

[latex]log_x(x-2)*log_x(x+2)=0[/latex] [latex]log_x(x-2)=0 [/latex] или [latex]log_x(x-2)=0[/latex] 1)[latex]log_x(x-2)=log_x1[/latex]  [latex]x-2=1[/latex] [latex]x=3[/latex] 2)[latex]log_x(x+2)=log_x1[/latex] [latex]x+2=1[/latex] [latex]x=-1[/latex]  Ответ: [latex] x_{1} = 3 [/latex]  [latex] x_{2} =-1[/latex]