Напишите разложение степини бинома ( х/2 - 3/y )^5

[latex](a+b)^5=a^5+5a^4b+10a^3b^2+10a^2b^3+5ab^4+b^5[/latex] [latex](\frac{x}{2}-\frac{3}{y})^5=(\frac{x}{2})^5-5(\frac{x}{2})^4\frac{3}{y}+10(\frac{x}{2})^3(\frac{3}{y})^2-10(\frac{x}{2})^2(\frac{3}{y})^3+5\frac{x}{2}(\frac{3}{y})^4-(\frac{3}{y})^5=\frac{x^5}{32}-\frac{15x^4}{16y}+\frac{90x^3}{8y^2}-\frac{270x^2}{4y^3}+\frac{405x}{2y^4}-\frac{243}{y^5}[/latex]