Найдите (a+9b+16) / (a+3b+8), если a/b=3

[latex] \frac{a}{b}=3\\\\ \frac{a+9b+16}{a+3b+8}= \frac{ \frac{a}{b}+ \frac{9b}{b}+ \frac{16}{b} }{ \frac{a}{b}+ \frac{3b}{b}+ \frac{8}{b} }= \frac{ \frac{a}{b}+9+ \frac{16}{b} }{ \frac{a}{b}+3+ \frac{8}{b} }= \frac{3+9+ \frac{16}{b} }{3+3+ \frac{8}{b} }= \frac{12+\frac{16}{b}}{6+\frac{8}{b}}=\\\\= \frac{ \frac{12b+16}{b} }{ \frac{6b+8}{b} }= \frac{12b+16}{6b+8}= \frac{4(3b+4)}{2(3b+4)}=2 [/latex]