Найдите корень уравнения (3х-2)*(х+4)-3*(х+5)*(х-1)=0

[latex](3x-2)(x+4)-3(x+5)(x-1)=0 [/latex]   [latex]3x^{2}+12x-2x-8-3(x^{2}-x+5x-5)=0[/latex]   [latex]3x^{2}+12x-2x-8-3x^{2}+3x-15x+15=0[/latex]   [latex](3x^{2}-3x^{2})+(12x-2x+3x-15x)+(-8+15)=0[/latex]   [latex]-2x+7=0[/latex]   [latex]2x=7[/latex]   [latex]x=7:2[/latex]   [latex]x=3,5[/latex] __________________________________________________________ [latex](3\cdot3,5-2)\cdot(3,5+4)-3\cdot(3,5+5)\cdot(3,5-1)=0 [/latex]   [latex](10,5-2)\cdot7,5-3\cdot8,5\cdot2,5=0 [/latex]   [latex]8,5\cdot7,5-63,75=0 [/latex]   [latex]63,75-63,75=0[/latex]   [latex]0=0[/latex]