Найдите корни квадратного трехчлена: а) 2х²+9х+4 б) х²+14х+48

[latex]2x^2+9x+4\\2x^2+9x+4=0\\D=81-32=49=7^2,D\ \textgreater \ 0\\x_{1,2}= \frac{-9б7}{4} = |{ {{-4} \atop {-0.5}} \right. \\OTBET:-4;-0.5\\\\x^2+14x+48\\x^2+14x+48=0\\D_1=( \frac{14}{2})^2 -48=49-48=1,D\ \textgreater \ 0\\x_{1,2}=-7б1=|{ {{-8} \atop {-6}} \right. \\OTBET:-8;-6[/latex]