Найдите область определения функции:√((x^2+2x+1)/(x-1)

[latex]y=\sqrt{\frac{x^2+2x+1}{x-1}}=\sqrt{\frac{(x+1)^2}{x-1}}=\frac{|x+1|}{\sqrt{x-1}}\\\\Tak\; kak\; |x+1| \geq 0\; \; pri\; \; x\in R,\; to\; \sqrt{x-1}\ \textgreater \ 0\; \Rightarrow \\\\x-1\ \textgreater \ 0,\; \; \; x\ \textgreater \ 1\\\\x\in (1,+\infty )\\\\ili\\\\\frac{(x+1)^2}{x-1} \geq 0\; ,\; \; \; ----[-1\, ]----(1)++++\\\\x\in (1,+\infty )[/latex]