Найдите общий корень уравнений [latex](x + 2) (x + 3) (x + 4) = 0[/latex] и [latex] \frac{x^2}{27} = \frac{1}{3} [/latex]

[latex](x + 2) (x + 3) (x + 4) = 0 \\\ \left[\begin{array}$ x + 2=0 \\ x + 3=0 \\ x + 4=0 \end{array}\right.\Rightarrow \left[\begin{array}$ x_1 =-2 \\ x_2 =-3 \\ x_3=-4 \end{array}\right.[/latex] [latex] \frac{x^2}{27} = \frac{1}{3} \\\ x^2=27\cdot \frac{1}{3} \\\ x^2=9 \\\ x=\pm3 [/latex] Общий корень уравнений равен -3.