Найдите решение системы 6(х+у) 8+2х-3у 5(у-х) 5+3х+2у

6х+6у х 8+2х-3у х5у-5х х 5+3х 2у=6х+10у х 40

[latex]\left\{{{6(x+y)=8+2x-3y}\atop{5(y-x)=5+3x+2y}}\right.\left\{{{6x+6y=8+2x-3y}\atop{5y-5x=5+3x+2y}}\right.\left\{{{6x+6y-2x+3y=8}\atop{5y-5x-3x-2y=5}}\right.\\\left\{{{4x+9y=8}\atop{3y-8x=5}}\right.\left\{{{4x+9y=8/2}\atop{3y-8x=5}}\right.\left\{{{8x+18y=16}\atop{3y-8x=5}}\right.[/latex] [latex]8x+18y+3y-8x=5+16\\21y=21;y=1\\----\\6(x+y)=8+2x-3y\\6(x+1)=8+2x-3\\6x+6=5+2x\\6x-2x=5-6\\4x=-1;x=-\frac{1}{4}=-0,25[/latex]