Найдите сумму корней биквадратного уравнения.4х^4-12х^2+1=0

[latex]4x^4-12x^2+1=0[/latex] [latex]y=x^2[/latex] [latex]4y^2-12y+1=0[/latex] [latex]D/4=36-4*1=32 (32=2^4*2)[/latex] [latex] y_{1}= \frac{6-4 \sqrt{2} }{4}=1,5- \sqrt{2} [/latex] [latex] y_{2}= \frac{6+4 \sqrt{2} }{4}=1,5+ \sqrt{2} [/latex] [latex]1,5- \sqrt{2} >0[/latex] [latex] x^{2} =1,5- \sqrt{2} [/latex] [latex] x_{1} =- \sqrt{1,5- \sqrt{2} } ; x_{2} = \sqrt{1,5- \sqrt{2} }[/latex] [latex] x^{2} =1,5+ \sqrt{2} [/latex] [latex] x_{3} =- \sqrt{1,5+ \sqrt{2} } ; x_{4} = \sqrt{1,5+ \sqrt{2} }[/latex] Сумма корней:[latex]: x_{1}+x_{2}+x_{3}+x_{4} =- \sqrt{1,5- \sqrt{2} }+ \sqrt{1,5- \sqrt{2} }+[/latex][latex]+(- \sqrt{1,5+ \sqrt{2} }) +\sqrt{1,5+ \sqrt{2} }=0.[/latex]